0=4x-(128/x^2)

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Solution for 0=4x-(128/x^2) equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

0 = 4*x-(128/(x^2)) // - 4*x-(128/(x^2))

128/(x^2)-(4*x)+0 = 0

128/(x^2)-4*x = 0

128*x^-2-4*x = 0

4*x*(32*x^-3-1) = 0

32*x^-3 = 1 // : 32

x^-3 = 1/32

-3 < 0

1/(x^3) = 1/32 // * x^3

1 = 1/32*x^3 // : 1/32

32 = x^3

x^3 = 32 // ^ 1/3

x = 2*4^(1/3)

4*x = 0

4*x = 0 // : 4

x = 0

x in { 0} 

x = 2*4^(1/3)

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